Prove that the maximum horizontal range is four times the maximum height attained by the projectile, when fired at an inclination so as to have maximum horizontal range - CBSE Class 11

Solved Vo = Initial speed The range R and the maximum height

Prove that the maximum horizontal range is four times the maximum height attained by the projectile; when fired at an inclination so as to have maximum horizontal range.

Prove that the maximum horizontal range is four times the maximum height attained by the projectile

If 'R' is the horizontal range and 'H' is the maximum height achieved by the projectile at an angle ''. Show that maximum range = (R^2/8H)+(2H) - gm11c4vv

A projectile is fired angle of 45^{circ} with the horizontal. Elevation angle of the projectile its heighest point as seen from the point of proejection, istan^{-1}left (dfrac {sqrt {3}}{2}right )45^{circ}60^{circ}tan^{-1}dfrac {1}{2}

SUPARNA From 157.36.180.178-XI-A-1552020-Physics-Assignment ch-3

Derive an expression for maximum height and range of an object in projectile motion.

3.3: Projectile Motion - Physics LibreTexts

The horizontal range of projectile is 4 times the maximum height

What is the angle at which a projectile has its maximum height and minimum horizontal distance traveled? - Quora

The horizontal range is four times the maximum height attained by a projectile.The angle of projection is (a)90^0 (b)60^0 (c)45^0 (d)30^0

Answer the following question. Derive the formula for the range and maximum height achieved by a projectile thrown from the origin with initial velocity u→ at an angle θ to the horizontal.